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Inessa05 [86]
2 years ago
14

You are dealt one card from a 52-card deck. Find the probability that you are dealt: a numbered card or a spade

Mathematics
2 answers:
Leto [7]2 years ago
8 0
In 52-card deck there are 36 numbered card and 52/4=13 spade card
 so probability that you are dealt a  numbered card is 36/52 =9/13  a spade card is 13/52=1/4
evablogger [386]2 years ago
6 0
So you start out with the 52 original cards. You know what 13 cards are spade shaped, and there are 10 numbered cards in each symbol. In total, 40 out of 52 cards are numbered, and 13 out of 52 are spade symbol. Now 10 out each symbol are numbered, start out with that. That equals 30 numbered cards. Now add the entire spade minideck, and you have 43 cards being the possibility. In numerical form, 43 out of the 52 cards are possible to be chosen. In fraction form, 43/52 will be your answer.
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Norma has an A-frame cabin.The back is shown below. How many square feet of paint will she need to cover the back of the cabin?
a_sh-v [17]
I FOUND YOUR FULL QUESTION IN OTHER FUENETES.
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3 years ago
A school has a population of 2500 students. The number of students is increasing at continuous growth rate of 4.5% each year. Wh
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Step-by-step explanation:

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2 years ago
If you had 12 pieces of licorice to share equally among 5 people, how much licorice would each
pentagon [3]
12÷5=1.5 of licorice will each person get
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3 years ago
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HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?
DiKsa [7]

Answer:

<h3>           B(10, 6)</h3>

Step-by-step explanation:

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then:

x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6

5 0
2 years ago
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vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

\\ \sf\dashrightarrow -9+8

\\ \sf\dashrightarrow -1

8 0
2 years ago
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