Answer:
Amounts in the intervall 
Step-by-step explanation:
We will take the variables c and s, where
c = amount to spend that month
s = savings of the month.
Since each month we save at least 100, we know that

Moreover, we earn $250 per month and we spend $20 in a kayaking club, which tells us that

and so

By multiplying by -1, the first inequality also tells us that

Consequently by adding 230 to the inequality, we get that

The slope is negative one
Given the graph of the function

and the graph of the function


when f(x) = g(x).
This occurs at the point(s) of intersection of the graphs of the function f(x) and g(x).
From the graph, we can approximate the points of intersection of the graphs of the function f(x) and g(x) to pe points
(-1.9, 13.7) and (2.7, 0).
Answer:
8/15 +5/15 = 12/15 = 4/5
Step-by-step explanation:
Answer:
1). g(-9) = -81.914
2). Last option
Step-by-step explanation:
1). f(x) = x²
For x = -9
f(-9) = (-9)² = 81
g(x) = 
g(-9) = ![\frac{32}{[2(-9)-17]}](https://tex.z-dn.net/?f=%5Cfrac%7B32%7D%7B%5B2%28-9%29-17%5D%7D)
= 
= -
(g - f)(-9) = g(-9) - f(-9)
= 
= 
= 
= -81.914
2). The relation is not a function because this function doesn't passes a vertical line test.
Last option will be the answer.