Solve the following system of equations 2x + y = 3 X = 2y - 1

Mathematics

1 answer:

pishuonlain [190]3 years ago

7 0

Answer:

x = 1 , y = 1

Step-by-step explanation:

Solve the following system:

{2 x + y = 3 | (equation 1)

x = 2 y - 1 | (equation 2)

Express the system in standard form:

{2 x + y = 3 | (equation 1)

x - 2 y = -1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 3 | (equation 1)

0 x - (5 y)/2 = (-5)/2 | (equation 2)

Multiply equation 2 by -2/5:

{2 x + y = 3 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 2 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

Answer: {x = 1 , y = 1

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