Letting "c" be the value of the temperature change, looking at the choices, the nearest answer would be C. " 76 + c; 76 + (–8) = 68; 68°F ".
76 is the base or current temperature, then c would be the change in temperature experience. Since a decrease of 8 degrees is to be experienced, it is denoted by the negative symbol on 8.
2/3 cup of oatmeal - 10 granola bars
When the number of cups of oatmeal increases, the number of granola bars also increases.
If you use for example twice as many cups of oatmeal, you'll make twice as many granola bars.
Therefore, the first step is to calculate how many times 20 cups of oatmeal is more than 2/3 cup of oatmeal. To do it, divide 20 by 2/3.

You have 30 times as many cups of oatmeal, so you'll make 30 times as many granola bars.

300 granola bars can be made with 20 cups of oatmeal.
Answer:
(x−3)(x−8)
Step-by-step explanation:

<u>Explanation</u>
Slope= 2/3
Y intercept= -2
x y
0 3
----------------
-2 0
Linear equations are those equations between variables that give a straight line when plotted on the graph.The standard form for linear equations in two variables is Ax+By=C.
linear equation refers implicitly to the case of just one variable. Here the linear equation 200x-300y=600 gives straight line when plotted on the graph.
The graph linear equation means the linear equation has to be plotted on the graph. After plotting it on the graph we get straight line passing x and y axis. The graph has been attached to the answer.
Answer:
5 km.
Step-by-step explanation:
We have to calculate the distance if we apply the speed formula that would be the distance in a given time:
v = d / t
therefore, if we solve for distance it would be:
d = v * t
Now the speed is 6 km / h but the time must be calculated, it leaves at 9:15 and returns at 10:05, that is, there is no exact time but 50 minutes, one hour equals 60 minutes, therefore:
50 min * 1 h / 60 min = 0.833 h, that is, the child took 0.833 hours to get to school, now if we replace:
d = 6 * 0.8333
d = 5
In other words, the distance between the school and the house is 5 km.