Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation = 
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:
For z = -1.56, we get:
For z = -0.88, we get:
Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
To find out is 3/20 is larger than 2 we will convert 3/20 to a decimal. Lets do it:-
3/20
3 ÷ 20 = 0.15
Is 0.15 larger than 2?
No, 0.15 is not larger than 2.
So, 3/20 isn't larger than 2.
Hope I helped ya!! xD
.68
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Answer:
2(x+3)=2x+6
2x+6=2x+6
Step-by-step explanation:
2(x+3)=2x+6
2x+6=2x+6
Answer:
The correct answer is 375 purple flowers.
Step-by-step explanation:
If all the F1 generation from true-breeding parents are purple than the genotype would be heterozygous i.e., Pp and Pp. Here P indicates the dominant allele which produces purple flower and p indicates the recessive allele of white flower.
So if we will cross the F 1 generation than the genotype would be PP, Pp, Pp, pp. That means 3 out of 4 offspring would be purple because three genotypes out of four have dominant purple allele(P).
So if out of 4 flower 3 is purple than according to calculation out of 500 flower 375 offspring would be purple(3/4*500= 375). Therefore the correct answer is 375 purple flowers should be produced.
