Equation of a circle that has a center at (h,k) and radius of r is
(x-h)²+(y-k)²=r²
so
given center (-1,2)
(x-(-1))²+(y-2)²=r²
(x+1)²+(y-2)²=r²
sub the other point to find r or r²
it passes through (2,-2)
sub 2 for x and -2 for y
(2+1)²+(-2-2)²=r²
(3)²+(-4)²=r²
9+16=r²
25=r²
5=r
the equation is
(x+1)²+(y-2)²=5²
Answer:
None
Step-by-step explanation:
Think about it. 4 is the x axis. -34 is the y axis. It will be located in quadrant IV.
Answer:
monomial
Step-by-step explanation:
because it has one variable which in this case is b and one number in this case is 10
Answer:
Option 3 or Option 4.
Step-by-step explanation:
I have this doubt because actually, a rhombus with a right angle (one) is not necessarily a square. Some rhombuses have one right angle and are still not squares. Now, if the four angles are right, it is a square, but this only says one.
On other hand, a parallelogram with congruent diagonals isn't a square necessarily either. Rectangles have congruent diagonals and are parallelograms.
In case you only can answer with one, I'll say is option 3, hope it helps!
Answer:
We have 7 complete teams
Step-by-step explanation:
Here, we have students preparing to make a team of 8 students per team. We now want to know how many complete teams they can make if they are a total of 60;
To get this, we need the multiples of 8;
we have;
8, 16 , 24 , 32, 40 , 48 , 56
So breaking it in 8s, we have;
8 8 8 8 8 8 8
We have 7 8s;
So there would be four left overs