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OlgaM077 [116]
2 years ago
12

Write a recursive rule for the sequence. –2, 4, –8, 16, . . .

Mathematics
1 answer:
VMariaS [17]2 years ago
4 0

a_{n} = (-2)^{n}

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What is the simplified expression
nignag [31]
The simplified answer would be 14x+17y-11
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A business office orders paper supplies from one of three vendors, V₁, V₂, or V₃. Orders are to be placed on two successive days
Dafna1 [17]

Answer:

a) P(A) = 0.33

b) P(B) = 0.56

c) P(AUB) = 0.78

d) P(A∩B) = 0.11

Step-by-step explanation:

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3 years ago
Three less than a 6 times a number is 39. find the number
Vanyuwa [196]
Using the problem, create an equation to find the number (x).
Three less than (so x minus 3) 6 times a number (6 times x) equals 39.

6x-3=39, solve for x.
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3 years ago
The graph of a proportional relationship passes through (9, 18) and (1, y). Find y.
spayn [35]

Answer:

2

Step-by-step explanation:

Because it's a proportional relationship and it goes through the point (9, 18) the equation is y = 2x so when x = 1, y = 2.

8 0
3 years ago
Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)
Bess [88]

Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

4 0
3 years ago
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