Write a recursive rule for the sequence. –2, 4, –8, 16, . . .
1 answer:
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Hello,
x,y,z∈ IN
==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
x,y,z∈ IN
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
Answer:
tan²x
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1
Divide all terms by cos²x
+
=
, that is
tan²x + 1 = sec²x ( subtract 1 from both sides )
tan²x = sec²x - 1