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3 years ago

A vertical line has a(n) ________ slope. a. undefined b. negative c. zero d. positive

Mathematics

1 answer:

Olin [163]3 years ago

8 0

C. Zero slope. If it's going straight up and down, there is no slope.

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PLEASE HELPPPPP

umka21 [38]

The answer is B I believe

4 0

2 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

1. Express 30 out of 40 and 40 out of 50 as a percentage. Which is<br> the better score?

Ymorist [56]

Answer:

30 out of 40: 75%

40 out of 50: 80%

40 out of 50 is the better score

5 0

3 years ago

Can someone please help?? what’s the measure of the vertex angle

maw [93]

Answer:

120 deg

Step-by-step explanation:

There is an angle symbol in the equilateral triangle and another symbol in half of the vertex angle. Those two angles are congruent.

The measure of the vertex angle is 2 * 60 deg = 120 deg

Answer: 120 deg

7 0

2 years ago

Please help, thank you :)

wolverine [178]

Answer:

y^6

Step-by-step explanation:

$\frac{y}{1} \times \frac{{y}^{5} }{1}$

${y}^{6}$

7 0

2 years ago