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Tju [1.3M]
2 years ago
14

Tony is using these numbers to make a new number.

Mathematics
2 answers:
RUDIKE [14]2 years ago
5 0

Answer:

wishes.

• He cannot use any number more than once.

• He cannot use powers.

• He cannot put numbers together, eg he can't use 147.

What is the biggest number he can make - show how he can make this number.

prohojiy [21]2 years ago
4 0

Answer:

<u>42</u><u>0</u>

Step-by-step:

<em>the</em><em> </em><em>only</em><em> </em><em>numbers</em><em> </em><em>that</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>use</em><em> </em><em>are</em><em> </em><em>12</em><em>,</em><em> </em><em>1</em><em>,</em><em> </em><em>4</em><em> </em><em>and</em><em> </em><em>7</em>

<em>we</em><em> </em><em>can</em><em> </em><em>use</em><em> </em><em>brackets</em><em>,</em><em>-</em><em>,</em><em>+</em><em>,</em><em>×</em><em>,</em><em> </em><em>as</em><em> </em><em>often</em><em> </em><em>as</em><em> </em><em>we</em><em> </em><em>want</em><em> </em>

<em>12</em><em> </em><em>and</em><em> </em><em>7</em><em> </em><em>are</em><em> </em><em>the</em><em> </em><em>largest</em><em> </em><em>numbers</em><em> </em><em>there</em><em> </em><em>so</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>times</em><em> </em><em>them</em><em>.</em><em>.</em><em>.</em><em> </em><em>that</em><em> </em><em>leaves</em><em> </em><em>4</em><em> </em><em>and</em><em> </em><em>1</em><em> </em><em>therefore</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>add</em><em> </em><em>them</em><em> </em><em>and</em><em> </em><em>times</em><em> </em><em>the</em><em> </em><em>result</em><em> </em><em>by</em><em> </em><em>(</em><em>12</em><em>×</em><em>7</em><em>)</em>

<em>so</em><em>.</em><em>.</em><em>.</em>

<em>(12×7)×(4+1)</em>

<em>12</em><em>×</em><em>7</em><em>=</em><em> </em><em>84</em>

<em>and</em><em>.</em><em>.</em><em>.</em>

<em>4</em><em>+</em><em>1</em><em>=</em><em>5</em>

<em>84</em><em>×</em><em>5</em><em>=</em><em> </em><u>420</u>

<u>thus</u><u>.</u><u>.</u><u>.</u><u>the</u><u> </u><u>largest</u><u> </u><u>number</u><u> </u><u>he</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>420</u>

Hope this helped you- have a good day bro cya)

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For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?
Gre4nikov [31]

The equation is separable, so solving it is trivial:

\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt

Integrating both sides gives

\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}

Given y(0)=24 and y(1)=18, we find

24=C

18=Ce^k=24e^k\implies e^k=\dfrac34\implies k=ln\dfrac34

so the answer is E.

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3 years ago
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Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the
nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

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25. a 2018 pew research center survey found that more americans believe they could give up their televisions than could give up
geniusboy [140]

(a)Probability that a person could give up cell phone = 0.48

(b)Probability that a person who could give up her cell phone also could give up television is 0.65

(c) Probability that a person who could not give up a cell phone could give up television is 0.73

What is Probability?

Calculating the likelihood of experiments happening is one of the branches of mathematics known as probability. We can determine everything from the likelihood of receiving heads or tails when tossing a coin to the likelihood of making a research blunder, for instance, using a probability. It is crucial to grasp this branch's most fundamental concepts in order to fully comprehend it, including the formula for computing probabilities in equiprobable sample spaces, the likelihood of two events joining together, the probability of the complementary event, etc.

According to  the given question:

a. Probability that a person could give up cell phone = 0.48

b. Probability that a person who could give up her cell phone also could give up television

= P(give up cell phone and TV)/p(give up cell phone)

= 0.31/0.48

= 0.6458

= 0.65

c. Probability that a person who could not give up a cell phone could give up television is

= P(could not give up cellphone and could give up TV)/P(could not give up cell phone)

= 0.38/0.52

= 0.73

d. The probability a person could give up television is higher for persons who couldn't give up cell phones than for those who could give up their cell phones.

Hence,

(a)Probability that a person could give up cell phone = 0.48

(b)Probability that a person who could give up her cell phone also could give up television is 0.65

(c) Probability that a person who could not give up a cell phone could give up television is 0.73

To learn more about Probability, visit:

brainly.com/question/13604758

#SPJ4

5 0
1 year ago
I will give brainiest for the correct answer
lord [1]
On the right hand side it should be m(x-x1)
Y-4=-3(x-5)
Y=-3x+19
5 0
3 years ago
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