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Vesna [10]
3 years ago
15

Which of the following shows 2 + (x + 3y) rewritten using the Associative Property of Addition?

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0
B (2+x) +3y

Other examples include <span>(14 + 6) + 7 = 14 + (6 + 7)
because </span><span>Adding 14 + 6 easily gives the sum of 20 to which we can add 7. The right hand side of the equation is where we add 14 and 13. Both sides will result in 27.</span>
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What is the area for this triangle
Llana [10]

Answer:

56

Step-by-step explanation:

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10

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Given: 20 yards of ribbon in total. Need to make 2 yards each.

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Where stocks sre traded can be called any of these EXCEPT
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Had to look for the options and here is my answer.
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3 0
3 years ago
Find the volume of the cereal box. Use the formula V=Bh.
Gwar [14]

Answer:

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Step-by-step explanation:

To find the volume of a box of cereal (also known as a rectangular prism) just multiply the area of the base (length times width) by the height. The formula is V = l · w · h. To find the volume of a box of cereal (also known as a rectangular prism) just multiply the area of the base (length times width) by the height.

7 0
3 years ago
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
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