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KiRa [710]
3 years ago
5

PLEASE HELP WITH THIS ONE QUESTION

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

dont know

Step-by-step explanation:

sorry

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Find the derivative
zalisa [80]

First use the chain rule; take y=\dfrac{x+5}{x^2+3}. Then

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}

By the power rule,

f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}

By the quotient rule,

y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}

So

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}

\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}

6 0
3 years ago
Simplify the expression and write without negative exponents:
andreyandreev [35.5K]
8sr6 + 2sr2×2×3 +5sr3 - sr2×3×3×3
=8sr6 + 2(2)sr3 + 5sr3 - 3sr2×3
=8sr6 + 4sr3 + 5sr3 - 3sr6
=8sr6 - 3sr6 + 4sr3 +5sr3
=5sr6 + 9sr3 (ans)
3 0
3 years ago
You purchased xyz common shares for $45 per share one year ago. one year later aftering receiving $4 dividend per share, you sol
Pepsi [2]
<span>The return for the investment is C, or 15.56%. You add the dividend and the capital gain, $4+$3=$7, and then divide by the initial investment price, or $45. 7/45=.1556, or 15.56%.</span>
7 0
3 years ago
Pls i will give brainliest<br> solve the equation: 3x^3-x^2=x^2
lora16 [44]

Answer:

x = 0 , 2/3

Step-by-step explanation:

3x^3-x^2=x^2

3x^3-2x^2=0

x^2(3x-2)=0

Now split into two equations:

1)

x^2=0

x=0

2)

3x-2=0

3x=2

x=2/3

3 0
2 years ago
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What is the equation of the line that passes through the point (-2,0) and has a slope of -2
Tcecarenko [31]

Answer:

y = -2x -4

Step-by-step explanation:

The equation of a line is y = mx + b, where m is the slope of the line, and b is the y-intercept.  We are told that the slope of the line is -2, so we can start with

y = mx + b

y = -2x + b

We can figure out the value of b by plugging in the coordinates of the point given (-2, 0)

0 = -2(-2) + b

0 = 4 + b

Subtract 4 from both sides of the equation

-4 = b

Then plug that value of b back into the equation above:

y = -2x + (-4) or y = -2x -4

6 0
3 years ago
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