3 years ago

Given g(x) = -2x + 1, solve for x when g(x) = 5.

Mathematics

2 answers:

Rudik [331]3 years ago

7 0

Here is the answer for you

madam [21]3 years ago

5 0

Answer:

g(5)=-2(5)+1

g(5)=-10+1

g(5)=-9

You might be interested in

How do you find the derivative of 4

Nutka1998 [239]

by rule the derivative of a constant is 0

so the answer for this is 0

5 0

3 years ago

How do i do this? i'm so lost. please explain and show your work

elena-s [515]

You want to make sure to factor each equation as much as you can first.
So just focus on the numerator first. $x^3-6x^2+8x$
To factor the numerator:
$(x)(x^2-6x+8)$ factor out an x
$(x)(x-4)(x-2)$ factor out the rest completely.

Now for the denominator: $-4x^2+4x+24$
$(-4)(x^2+x+6)$ factor out a -4
$(-4)(x+3)(x-2)$ factor out the rest.

This leaves you with:
$\frac{(x)(x-4)(x-2)}{(-4)(x+3)(x-2)}$

Then you can simplify:
$\frac{(x)(x-4)}{(-4)(x+3)}$

I'm not sure what you're supposed to find exactly, so if you need more help you can ask me (:

8 0

4 years ago

If (x)=x/2-2 and g(x)=2x2+x-3, find (f+g)(x)

Lady_Fox [76]