7.70 and 7.700 they are all the same since the 7 tenths are still in its place
For this problem you have to isolate the variable. To do this you must inverse the operations. Multiply 18 by 5, then divide by 12 to get your answer of 7.5
• The ball is at the same height as the building between 8 and 10 seconds after it is thrown. TRUE - the height is zero somewhere in that interval, hence the ball is the same height from which it was thrown, the height of the roof of the building.
• The height of the ball decreases and then increases. FALSE - at t=2, the height is greater than at t=0.
• The ball reaches its maximum height about 4 seconds after it is thrown. TRUE - the largest number in the table corresponds to t=4.
• The ball hits the ground between 8 and 10 seconds after it is thrown. FALSE - see statement 1.
• The height of the building is 81.6 meters. FALSE - the maximum height above the building is 81.6 meters. Since the ball continues its travel to a distance 225.6 meters below the roof of the building, the building is at least that high.
1. TRUE
2. False
3. TRUE
4. False
5. False
EF and GH. those are the right answers
Answer:
x = 30
Step-by-step explanation:
here 50 is hypotenuse as it is opposite of 90 degree.
x and x + 10 are the two other smaller sides of a right angled triangle respectively.
using pythagoras theorem,
a^2 + b^2 = c^2
x^2 + (x + 10)^2 = 50^2
x^2 + x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 - 2500 = 0
2x^2 + 20x - 2400 = 0
2(x^2 + 10x - 1200) = 0
x^2 + 10x - 1200 = 0
x^2 + (40 - 30) - 1200 = 0
x^2 + 40x - 30x - 1200 = 0
x(x + 40) - 30(x + 40x) = 0
(x + 40)(x - 30) = 0
either x + 40 = 0 OR x - 30 = 0
x = 0 - 40
x = -40
x - 30 = 0
x = 30
x = -40,30
since the length and distance is not measured in negative ur answer will be 30
credit goes to sreedevi102
thank u very much . At first i was wrong and giannathecookie i m really sorry
