The answer is equal to 10.
x = 2
<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).
Step-by-step explanation:
f(x) = x³ - 3x² + 12 in interval [-2, 4]
{taking f'(x) by doing derivative of f(x)}
f'(x) = 3x² - 6x
.•. f'(x) = 0
0 = 3x² - 6x
0 = 3x(x - 2)
0 = x - 2
x = 2
You might have made an error the first time you solved for x. I got x = -0.5.
When you have your log base 4, the way you cancel that out is by making 4 the base on both sides, so you get 4^(log4) to reduce to 1, and you're left with:
2x + 3 = 4^(1/2) ... Simplify
2x + 3 = 2
2x = -1
x = -1/2
If you plug that back in, everything checks out. Maybe double check your use of logarithm/exponent properties?
Answer:
false for 0.7 it would have to be 7/10
Step-by-step explanation:
