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OleMash [197]
2 years ago
6

Five less than the area of a square is 59 square feet. Find the side length of the square.​

Mathematics
1 answer:
In-s [12.5K]2 years ago
6 0

Answer:

4 feet

Step-by-step explanation:

Let the side length of the square be x feet.

x^2 - 5 = 59

x^2 = 64

x = ±4 (reject - 4 since length > 0)

Topic: Areas of polygons

If you would like to venture further, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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Factorise the expression: am^2 + bm^2 + bn^2+an^2​
Pani-rosa [81]

Answer:

( a+b) ( m^2 + n^2)

Step-by-step explanation:

factorise like terms

m^2 ( a + b ) + n^2 ( m^2 + n^2)

then put like terms together put remaining terms in a bracket

( a + b) ( m^2 + n^2 )

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Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −
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Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

(x-h)^2+(y-k)^2=r^2

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

x^2 +y^2 - 4x+ 4y - 10 = 0  \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

x^2 +y^2 - 8x - 6y - 20 = 0   \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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Answer:

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Step-by-step explanation:

Consider the given equation

y=x^2-6x+8

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So, we need to find the factored form of the given equation.

Splinting the middle term we get

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p=4,q=2

It means x-intercepts of the given parabola are 4 and 2.

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