Answer =
1. SAS
2. SSS
3. ASA
4. SSS
5. SAS
6. AAS
Answer:147.57
Step-by-step explanation:
Sum of two sides of the triangle should be more than 3d side.
n<20+5,
n<25
Third side should be more than difference of two other sides.
n> 20-15
n>5
So, n should be
5<n<25.
Subtract four from both sides. That'll put both numbers without a variable on one side, and the number with the variable is by itself.
Answer:
Step-by-step explanation:
let : x The length and y the width you have this system :
xy =60....(1)
x = y+10...(2)
put the value for x in (1): (y+10)y =60
the quadratic equation is : y² +10y - 60 = 0
Δ =b² - 4ac a = 1 b= 10 c= - 60
Δ =10² - 4(1)(-60) = 324 =18²
y 1 = (-10-18)/2 negatif...... refused
y 2 = (-10+18)/2 =4
the width is 4
