Answer:
exit ticket
1.) 6+8x
2.) 18+6x^5
homework module 4 lesson 6
1.) 78
2.) 61
3.) 24
Step-by-step explanation:
Answer:
The sides of a right triangle all right triangles fall under the identity a^2 + b^2 = c^2. Thus, if you draw the picture, you know that both a and b will be 32 feet. You plug 32 in, and get 32^2 + 32^2 =2048. The square root of 2048=45.25 ft. Thus, the diagonal will be 45.25 feet.
Step-by-step explanation:
this is the correct formula to figure out equal sided right triangle
Answer:
Pretty sure it is D.
Step-by-step explanation:
How I think the narrator was thinking: I mean, yes, its a wedding on Saint Patricks, but you still need to dress appropriatley (its a wedding)
Answer:
![\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Csim%20N%28%5Cmu%20%2C%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%29)
And replacing:
![\mu_{\bar X}= 5](https://tex.z-dn.net/?f=%20%5Cmu_%7B%5Cbar%20X%7D%3D%205)
And the deviation:
![\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126](https://tex.z-dn.net/?f=%20%5Csigma_%7B%5Cbar%20X%7D%3D%20%5Cfrac%7B0.283%7D%7B%5Csqrt%7B5%7D%7D%3D%200.126)
And the distribution is given:
![\bar X \sim N(\mu= 0.08, \sigma= 0.126)](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Csim%20N%28%5Cmu%3D%200.08%2C%20%5Csigma%3D%200.126%29)
Step-by-step explanation:
For this case we have the following info given :
![\mu= 5. \sigma^2 =0.08](https://tex.z-dn.net/?f=%20%5Cmu%3D%205.%20%5Csigma%5E2%20%3D0.08)
And the deviation would be ![\sigma = \sqrt{0.08}= 0.283](https://tex.z-dn.net/?f=%20%5Csigma%20%3D%20%5Csqrt%7B0.08%7D%3D%200.283)
For this case we select a sample size of n = 5 and the distirbution for the sample mean would be:
![\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Csim%20N%28%5Cmu%20%2C%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%29)
And replacing:
![\mu_{\bar X}= 5](https://tex.z-dn.net/?f=%20%5Cmu_%7B%5Cbar%20X%7D%3D%205)
And the deviation:
![\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126](https://tex.z-dn.net/?f=%20%5Csigma_%7B%5Cbar%20X%7D%3D%20%5Cfrac%7B0.283%7D%7B%5Csqrt%7B5%7D%7D%3D%200.126)
And the distribution is given:
![\bar X \sim N(\mu= 0.08, \sigma= 0.126)](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Csim%20N%28%5Cmu%3D%200.08%2C%20%5Csigma%3D%200.126%29)
I'm going to assume that they are on parallel tracks, and not the same track.
60x=40(x+2)
60x=40x+80
20x=80
x=4
You can check the work I've provided by filling in the answer for x into the initial question.
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