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2 years ago

How might you prove your observations from question 4 about the length of a midsegment using geometric theorems?

1 answer:

6 0

Answer:To prove the relationship about the length of a midsegment, I can use the properties of parallel lines and transversals. If I draw at least two midsegments, I see that they form congruent triangles within the original triangle, ∆ABC. I can prove the congruence of these triangles using triangle congruence criterion, and then use properties of congruent triangles and the Transitive Property to show that the length of the midsegment is half the length of the side it is parallel to.

Step-by-step explanation:

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Find the measure of the indicated angle. Round to the nearest tenth.

erik [133]

Answer:

Step-by-step explanation:

cos θ=12/16=3/4=0.75

θ=cos^{-1}(0.75)≈41.4°

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3 years ago

Suppose a car is initially worth $20,000, and suppose that after one year, the car is now worth $18,673. Write an exponential fu

ArbitrLikvidat [17]

Subtract and it will work

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2 years ago

One ball is to be selected from a box containing red, white, blue, yellow, and green balls. If the probability that the selected

ZanzabumX [31]

Answer:

30% probability that it will be yellow, or green

Step-by-step explanation:

The urn has red, white, blue, yellow, and green balls.

Each ball is chosen with the following probabilities:

1/10 = 10% probability it is red

2/5 = 40% probability it is white

1/5 = 20% probability it is blue.

p probability it is yellow or green

What is the probability that it will be yellow, or green

The sum of all probabilities is 100%. So

10 + 40 + 20 + p = 100

p = 30

30% probability that it will be yellow, or green

5 0

3 years ago

A 15 ounce alloy containing 30% gold was mixed with an alloy containing 5% gold to get an alloy containing 20% gold. How many ou

Studentka2010 [4]

Answer:

4.5 % alloy

Step-by-step explanation:

Let x = amt of 30% alloy

The resulting total is to be 25 oz, therefore:

(25-x) = amt of 5% alloy:

A typical mixture equation:

.30x + .05(25-x) = .20(25)

.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25

.25x = 3.75

x = 3.75%2F.25

x = 15 oz of 30% alloy required

then

25-15 = 10 oz of 5% alloy:

Check solution

.30(15) + .05(10) = .20(25)

4.5 + .5 = 5

4 0

3 years ago

Given ⊙A, an angle ∠CDB is inscribed with ∡CDB=43°. A second angle, ∠CEB, is inscribed. Find ∡CEB.

wel

180 Fosho Fosho I think

5 0

2 years ago