What is the total amount of fees if there were 6 withdrawals for cash in a month, 10 uses of an ATM,

Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph

Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

$f(x)=x^4-x^3-7x^2+13x-6$ .

We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

$f(-3)=81+27-63-39-6$

$f(-3)=6-6$

$f(-3)=0$

Also

$f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6$

$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

$x=2$ and $x=-3$ have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.

Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

4 0

3 years ago

A 9-kilogram bag of cement costs $12.22. What is the unit price, rounded to the nearest cent

Alekssandra [29.7K]

1.36 because 12.22/9=1.36

3 0

3 years ago

The domain of this function is {-12, -6, 3, 15}. y=-2/3x+7 complete the table based on the given domain.

Nookie1986 [14]

If the domain of the function y=-2/3 x+7 is {-12,-6,3,15} then the range of the function is {15,11,5,-3}.

Given that the domain of the sunction y=-2/3 x+7 is {-12,-6,3,15}.

We have to find the range of the function and complete the table.

Function is relationship between two or more variables expressed in equalto form. In a function each value of x has some value of y.

To complete the table we need to find the value of the function at different values of x.Domain is basically value of x which satisfies the function.

We have to first put the value of x=-12 in y=-2/3+7

y--2/3*-12+7

=15

Now put x=-6 in the function.

y=-2/3 *-6+7

=3

Put the value of x=3 in the function.

y=-2/3*3+7

=5

Put the value of x=15.

y=-2/3*15+7

=-41/3.

Hence the range of function is {15,11,-41/2,5}.

Learn more about range at brainly.com/question/26098895

#SPJ4

8 0

1 year ago

Trig question<br> Please help

melomori [17]

Answer:

2+2=4

Step-by-step explanation:

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5 0

3 years ago

Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and

NemiM [27]

Answer:

$P(9\cup queen)=\frac{2}{13}$

Step-by-step explanation:

Total number of cards $=52$

Total cards of $9$ $=4(1\ club,1\ diamond,1\ heart,1\ spades)$

Total cards of Queen $=4(1\ club,1\ diamond,1\ heart,1\ spades)$

Total number of elements in $9\cup Queen$ $=8$

$P(9\cup queen)=\frac{elements\ in\ 9\cup queen}{Total\ number\ of\ elements}\\\\P(9\cup queen)=\frac{8}{52}=\frac{2}{13}$

7 0

3 years ago