Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
Answer:
65
Step-by-step explanation:
according to the question
3x-1=0
3x=1
x=⅓
so
f(x)=18x³+x-1
f(⅓)=18.(⅓)³+⅓-1
f(⅓)=18.⅓.⅓.⅓+⅓-1
f(⅓)=6.⅑+⅓-1
f(⅓)=⅔+½-1
f(⅓)=0
<h3>therefore</h3><h3> the remainder is 0</h3>
Answer:
1)B
2)C
3)B
4)A
5)C
Step-by-step explanation:
BrainLiest please
