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4 years ago

Complete the pattern 5, 10, 30, 60, 180, _____?????

Mathematics

2 answers:

Lesechka [4]4 years ago

6 0

5*2=10 10*3=30 30*2=60 60*3=180 180*2=360

34kurt4 years ago

4 0

Answer: the next term will be 360.

Explanation:

Since we have given that

$5,10,30,60,180,........$

There is a pattern followed, i.e. :

$5\times 2=10\\\\10\times 3=30\\\\30\times 2=60\\\\60\times 3=180$

It means first term is multiplied by 2 to get the second term ,

Second term is multiplied by 3 to get the third term,

Third term is multiplied by again 2 to get the fourth term,

Fourth term is multiplied by again 3 to get the fifth term,

So, we need to calculate the sixth term , by following this pattern we get that

$180\times 2 = 360$

So, the next term will be 360.

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natali 33 [55]

Answer:

We conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same.

Step-by-step explanation:

We are given that in a previous poll, 40% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week.

Suppose that, in a more recent poll, 456 of 1194 adults with children under the age of 18 reported that their family ate dinner together seven nights a week.

Let p = proportion of families with children under the age of 18 who eat dinner together seven nights a week.

SO, Null Hypothesis, $H_0$ : p $\geq$ 40% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same}

Alternate Hypothesis, $H_A$ : p < 40% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of families with children under the age of 18 who eat dinner together seven nights a week = $\frac{456}{1194}$ = 0.38

n = sample of adults = 1194

So, the test statistics = $\frac{0.38-0.40}{\sqrt{\frac{0.38(1-0.38)}{1194} } }$

= -1.424

The value of z test statistics is -1.424.

Now, at 0.01 significance level the z table gives critical value of -2.326 for left-tailed test.

Since our test statistic is more than the critical value of z as -1.424 > -2.326, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same.

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