Student council is making bows for Red Ribbon Week. To make a complete bow, they need 234 feet of ribbon. If the student council
2 answers:
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Answer:
Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.
Step-by-step explanation:
We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.
<em>Let </em><em> = sample proportion of Americans who can order a meal in a foreign language</em>
The z-score probability distribution for sample proportion is given by;
Z = ~ N(0,1)
where, = sample proportion
p = population proportion of Americans who can order a meal in a foreign language = 0.47
n = sample of Americans = 200
Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( > 0.50)
P( > 0.06) = P(
>
) = P(Z > 0.85) = 1 - P(Z
0.85)
= 1 - 0.80234 = <u>0.19766</u>
<em>Now, in the z table the P(Z </em> <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>
Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.
Answer:
(2, - 6 )
Step-by-step explanation:
Given the 2 equations
x = y + 5 → (1)
2x + 3y = - 14 → (2)
Substitute x = y + 5 into (2)
2( y + 5 ) + 3y = - 14 ← distribute and simplify left side
y + 10 + 3y = - 14
4y + 10 = - 14 ( subtract 10 from both sides )
4y = - 24 ( divide both sides by 4 )
y = - 6
Substitute y = - 6 into (1) for corresponding value of x
x = (0.5 × - 6 ) + 5 = - 3 + 5 = 2
Solution is (2, - 6 )