BRAINIEST answer this question and I'll give you brainiest

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

Heellllppppppppppppppp

Korolek [52]

Answer:

106

Step-by-step explanation:

angle c = 180-74 = 106

8 0

2 years ago

Read 2 more answers

F(x)=-x^2+8x-11 find the value of f(-1)-f(1)

IrinaVladis [17]

Answer: The answer is (4,5)

Step-by-step explanation:

5 0

2 years ago

Several students were asked to name the kinds of animals they saw in the past week at the park. Determine the ratio that compare

SVETLANKA909090 [29]

Answer:

A. 1:8

Step-by-step explanation:

We have been given that several students were asked to name the kinds of animals they saw in the past week at the park.

Dogs: 8

Cat: 2

Fish: 4

Lizard: 2

We are asked to find the ratio that compares the number of cats seen to the total number of animals seen.

Let us find total number of animal by adding each type of animals as:

$\text{Total animals}=8+2+4+2$

$\text{Total animals}=16$

We can see that the students saw 2 cats, so ratio of cats to total animals would be $2:16$ .

Dividing 2 and 16 by 2, we will get:

$\frac{2}{2}:\frac{16}{2}\Rightarrow 1:8$

Therefore, the ratio 1:8 compares the number of cats seen to the total number of animals seen and option A is the correct choice.

5 0

2 years ago

write an equation of the line that is parallel to the line whose equation is 4y+9=2x and passes through the point (7,2)

Liula [17]

Ok so we’ll put the first equation into slope int form

4y=2x-9

y=1/2x -4/9

since the likes are parallel, the slope of the line we are trying to write an equation for is 1/2

equation:

y-2=1/2(x-7)

7 0

2 years ago