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sladkih [1.3K]
2 years ago
11

Three consecutive odd integers add to −9. What are these integers?

Mathematics
1 answer:
Marat540 [252]2 years ago
8 0
Let the number be x.

1st number = x
2nd number = x + 2
3rd number = x + 4

x + x + 2 + x + 4 = -9
3x + 6 = -9
3x = -15
x = -5


1st number = x = -5 
2nd number = x + 2 = -3
3rd number = x + 4 = -1

Answer: The numbers are -1, -3, and -5
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3 years ago
Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9
AnnZ [28]

Answer:

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

Step-by-step explanation:

We have been given that

f(x)=x^3-27,g(x)=3x-9

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes -  a^3-b^3=(a-b)(a^2+ab+b^2)

f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)

And g(x) can be written as

g(x)=3x-9\\=3(x-3)

Thus, we have

(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}

On cancelling the common factors, we get

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

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Answer:

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3 years ago
12 divided by 5/6 (pretty easy but im lazy)&lt;3
Mumz [18]

Answer:

14.4

Step-by-step explanation:

Hope this helps you :)

6 0
3 years ago
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