Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate,
= 6 boats per hour.
Service rate,
= 10 boats per hour.
Probability of zero boats in the system,
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
=
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
It is the detailed record of all the changes in a specific asset, liability, or stockholder's equity item as a result of transaction. Hope this helps!
Answer:
The marginal propensity to save is 0.4
Explanation:
The marginal propensity to save is 1 - marginal propensity to consume.
The marginal propensity to consume is the proportion of an increase in income that the consumers will spend from this increased income and the marginal propensity to save is the proportion of the increase in income that will be saved.
The marginal propensity to consume (MPC) = Change in consumption / change in income
The MPC = (2100 - 1500) / (3000 - 2000) = 0.6
Thus, the marginal propensity to save is 1 - 0.6 = 0.4
Answer:
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Explanation:
The gift to the grandaughter is <span>Partially shielded by the annual gift tax exclusion. In the year of 2016, the federal government created </span><span>the </span>estate<span> and gift </span>tax exemption<span> is $5.45 million per individual.
Which means that the inheritence that given to the granddaughter would be tax free as long as it does not surpass the net value of 5.45 million.</span>