Answer:
see below
Step-by-step explanation:
A discriminant value of zero means there is exactly one x-intercept. The graph below has that characteristic.
_____
<em>Comment on discriminant</em>
discriminant > 0, two (2) x-intercepts (first 2 graphs)
discriminant < 0, no (0) x-intercepts (third graph)
It should be (X,Y)=(15/8,-25/4)
Answer:
Use continuity to evaluate the limit.
lim 16+radical x/ radical 16+x
1+9
Consider the intervals for which the numerator and the denominator are continuous.
The numerator 16+ radical x is contintuous on the interval
[0,00)
0
The denominator V16 + I is continuous and nonzero on the interval
(16,00)
X
The interval for which the quotient is continuous is the intersection of the above intervals.
16+
Therefore, the quotient
is continuous on the interval
716 +1
[-16,0]
X
Since 2
9 is in the interval (0, 0), then fis continuous at x = 9. Therefore,
19
16 + VE
lim
179 16 +2
f(9)
00
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Step-by-step explanation:
-6(2+a) = -48
Distributive property
-12 -6a = -48
Add 12 to both sides
-6a = -36
Divide both sides by -6 and you get a= 6