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Llana [10]
3 years ago
10

Which statement BEST explains the relationship between the numbers divisible by 6,2 and 3?

Mathematics
2 answers:
love history [14]3 years ago
8 0
A. A number that is divisible by 6 is also divisible by 2 and 3 because 2 and 3 are factors of 6.
Anuta_ua [19.1K]3 years ago
6 0

Answer:

A. A number that is divisible by 6 is also divisible by 2 and 3 because 2 and 3 are factors of 6.

Step-by-step explanation:

2 and 3 are prime numbers, whose product is equal to 6. Besides, 2 is an even number, while 3 is an odd number, and the product of an even number and an odd number is equal to an even number. Therefore, All number that is divisible by 6 are also divisible by 2 and 3, both prime numbers. In conclusion, the right answer is A.

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Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)
damaskus [11]

The product is equal to zero if one of the factors is equal to zero.

Therefore:

y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}

5 0
4 years ago
When the domain of a function has an infinite number of values, the range always has an infinite number of values. True or false
iragen [17]

Answer:

Thus, the statement is False!

Step-by-step explanation:

When the domain of a function has an infinite number of values, the range may not always have an infinite number of values.

For example:

Considering a function

f(x) = 5

Its domain is the set of all real numbers because it has an infinite number of possible domain values.

But, its range is a single number which is 5. Because the range of a constant function is a constant number.

Therefore, the statement ''When the domain of a function has an infinite number of values, the range always has an infinite number of values'' is FALSE.

Thus, the statement is False!

3 0
3 years ago
Graph the circle which is centered at (3,-2) and has a radius of 5 units.
goldenfox [79]

Answer:

(x-3)^2+(y+2)^2=25

Step-by-step explanation:

c=(a,b) coordinates of center of circle

(x-a)^2+(y-b)^2=r^2 circle equation

a=3  b=-2  r=5

(x-3)+(y+2)=5^2

(x-3)^2+(y+2)^2=25

4 0
4 years ago
How many five-digit numbers are there that contain the digit 1 (at least) three times in a row?
My name is Ann [436]

Answer:

So you say you want some 5 digit numbers eh? Let’s consider some boundaries. 5 digit numbers range from 10,000 - 99,999. So our number is guaranteed to be between 0 and 90000.

Sometimes it’s much easier to work with concrete things. Such as the number of numbers that don’t contain any 3s. It’s really more difficult to put our finger on “at least 1” anything so we try to steer clear of it.

Anyways we’ve got 90000 numbers that have at least 1 or 0 3’s. Find one and we know the other.

So no 3’s at all right? Well you have 8 choices for the first digit (can’t choose 0 and you can’t choose 3). And then for the remaining 4 digits you have 9 choices. So that’s

8∗94=52488  

Back to our initial equation, we have

90000−8∗94=37512  5 digits numbers without any 3s.

A quick (or maybe not so quick) matlab script confirms such calculations.

credits to : Trevor Squires

7 0
3 years ago
If 2×2=4 and 4×4=8. What is 8×8?​
Oxana [17]

Answer:

64

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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