The product is equal to zero if one of the factors is equal to zero.
Therefore:
Answer:
Thus, the statement is False!
Step-by-step explanation:
When the domain of a function has an infinite number of values, the range may not always have an infinite number of values.
For example:
Considering a function
Its domain is the set of all real numbers because it has an infinite number of possible domain values.
But, its range is a single number which is 5. Because the range of a constant function is a constant number.
Therefore, the statement ''When the domain of a function has an infinite number of values, the range always has an infinite number of values'' is FALSE.
Thus, the statement is False!
Answer:
(x-3)^2+(y+2)^2=25
Step-by-step explanation:
c=(a,b) coordinates of center of circle
(x-a)^2+(y-b)^2=r^2 circle equation
a=3 b=-2 r=5
(x-3)+(y+2)=5^2
(x-3)^2+(y+2)^2=25
Answer:
So you say you want some 5 digit numbers eh? Let’s consider some boundaries. 5 digit numbers range from 10,000 - 99,999. So our number is guaranteed to be between 0 and 90000.
Sometimes it’s much easier to work with concrete things. Such as the number of numbers that don’t contain any 3s. It’s really more difficult to put our finger on “at least 1” anything so we try to steer clear of it.
Anyways we’ve got 90000 numbers that have at least 1 or 0 3’s. Find one and we know the other.
So no 3’s at all right? Well you have 8 choices for the first digit (can’t choose 0 and you can’t choose 3). And then for the remaining 4 digits you have 9 choices. So that’s
8∗94=52488
Back to our initial equation, we have
90000−8∗94=37512 5 digits numbers without any 3s.
A quick (or maybe not so quick) matlab script confirms such calculations.
credits to : Trevor Squires
Answer:
64
Step-by-step explanation:
