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maria [59]
3 years ago
13

11 El prisma tiene 9 caras, 9 aristas y 6 vertices. (2 puntos) Cierto Falso 1

Mathematics
1 answer:
Levart [38]3 years ago
4 0
Hi! I don’t know what any of this means but I hope you have an amazing day and I hope god/allah/etc. blesses you :)
sorry I couldn’t answer
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Find the distance between these points: (-3, 8) and (-5,1)
irina1246 [14]

Answer:

7.28011

Step-by-step explanation:

X1 =-3

X2 =-5

Y1 =8

Y2 =1

Distance Formula = √(X2-X1)²+ (Y2-y1)²

Step 1. calculate (X2-X1)²

(-5 - -3)2 = 4

Step 2. calculate (Y2-Y1)²

(1 - 8)2 = 49

Step 3. calculate √4 + 49

                = 7.28011

5 0
3 years ago
Need answer!! please help.
defon

Answer:

I think A

Step-by-step explanation:

8 0
2 years ago
Find the Domain and range of each relation. <br> 1. Q= {(3,4), (-4,1), (2,5), (-4,1), (0,0)}
zimovet [89]

Answer:

Step-by-step explanation:

domain is all ur x values.....

domain = { -4,0,2,3}....u only have to write them once if they repeat

range is all ur y values....

range = { 0,1,4,5}

7 0
3 years ago
Based only on the information given in the diagram, which congruence
Brilliant_brown [7]

Answer:

I think B and C

Step-by-step explanation:

Because they are the only ones that have more than two so you know it would be them

5 0
3 years ago
Read 2 more answers
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
Read 2 more answers
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