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Margarita [4]
3 years ago
8

Erica makes necklaces from beads. Each necklace consists of blue, white and green beads in the ratio of 6 : 4: 1 One necklace ne

eds to have 44 beads. How many of each type of bead is needed to make the necklace?
Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

<u>For one Necklace you would need...</u>

24 blue beads.

16 white beads.

4 green beads.

Ratio: 24: 16: 4

Step-by-step explanation:

If you quadruple the amount of beads from the original amount (6 : 4: 1), the total beads for that necklace will be 44.

Step 1: 6 x 4 = 24 (amount of blue beads in necklace).

Step 2: 4 x 4 = 16 (amount of white beads in necklace).

Step 3: 1 x 4 = 4 (amount of green beads in necklace).

Now check to see if the total of all types of beads sum up to 44:

Step 4: 24 + 16 + 4 = 44

______________-

There is your answer:

You need 24 blue beads, 16 white beads, and 4 green beads to have a total sum of 44 beads in that one necklace.

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Hope it helps!

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3 years ago
If a and b are the measures of two first quadrant angles and sin a = 4/9 and sin b = 2/5 find sin(a+b).
frutty [35]

Answer:

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}

Step-by-step explanation:

we are given

sin(a)=\frac{4}{9}

sin(b)=\frac{2}{5}

Firstly, we will draw triangle

we get

cos(a)=\frac{\sqrt{65} }{9}

cos(b)=\frac{\sqrt{21} }{5}

now, we can sue formula

sin(a+b)=sin(a)cos(b)+cos(a)sin(b)

now, we can plug values

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now, we can simplify it

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}


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