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Norma-Jean [14]
3 years ago
13

What is the smallest number that rounds to 45 000 when round off to the nearest thousand​

Mathematics
2 answers:
suter [353]3 years ago
5 0

The least number which can be rounded off to 45,000 is 44,500. While the largest is 45,499.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

sergeinik [125]3 years ago
4 0

Answer:

44 500

Step-by-step explanation:

When 44 499 is round off to nearest 1000,answer is 44 000.Therefore this is the smallest no. the rounds to 45 000

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MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
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Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
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               = 72
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2.
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It’s C since it is open and x is less than 2. We can plug in any number on the number line to see if this makes sense.
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(3/4)/3

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