Question

Someone help me out!

Answer 1

Given:-

$\red{➤}\:$$\sf f(x) = 2x^3-5x^2-3x$

$\red{➤}\:$$\sf g(x)=x$

To Find:-

$\orange{☛}\:$$\sf h(x)$

Solution:-

$\begin{gathered}\\\quad\longrightarrow\quad\sf h(x) =f(x)÷g(x) \\\end{gathered}$

$\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{f(x)}{g(x)}= \dfrac{2x^3-5x^2-3x}{x} \\\end{gathered}$

$\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{x(2x^2-5x-3)}{x} \\\end{gathered}$

$\begin{gathered}\\\quad\longrightarrow\quad\sf 2x^2-5x-3 \\\end{gathered}$

$\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf{h(x)= 2x^2-5x-3}} \\\end{gathered}$