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Kay [80]
3 years ago
9

Easy variable question pls help

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

z = -4 1/2

Step-by-step explanation:

1. First change the mixed fractions to improper fractions so it's easier

\frac{16}{5\\}/(z-\frac{1}{2}) = \frac{8}{3}/(z+\frac{1}{3})

2. Simplify

\frac{32}{5(2z-1)} = \frac{8}{3z+1}

3. Cross multiply

32(3z+1) = 5(2z-1) * 8

4. Simplify again (distributive property)

32(3z+1) = 40(2z-1)

5. Distributive property

32(3z+1) -> 96z+32  

40(2z-1) -> 80z-40

96z+32=80z-40

6. Subtract 32 from both sides

96z+32-32 = 80z-40-32

7. Simplify

96z = 80z-72

8. Subtract 80 from both sides

96z-80z=80z-72-80z

9. Simplify

16z=-72

10. Divide both sides by 16

\frac{16z}{16}=\frac{-72}{16}

11. Simplify

z=-\frac{9}{2} -> also = -4\frac{1}{2}

Sorry if it was too long but hope this helps! :)

And also try using symbolab cuz it gives step by step explanations it's really good!

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The sum of two numbers is 27. One number is seven less than the other. Find the numbers
Marat540 [252]

Answer:

17 and 10

Step-by-step explanation:

Write the problem as an equation.

a+b=27

a=b-7

Where a and b are the two numbers you are trying to find. You could use any variables. Then solve.

b+(b-7)=27      Sub (b-7) for a

2b-7=27          Group like terms

2b=34             Add 7 to both sides

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Because b=17, a must be 10.

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sveticcg [70]

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224

Step-by-step explanation:

To make this easier, multiply all the measurements by 3, so you have 1 inch cubes with a box of 8 in. width, 4 in. length, and 7 in. height. This makes it a lot easier to understand as it is finding the volume of the cube, which is width x length x height. This is 8 * 4 * 7 which is 224. - Madison P.

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3 years ago
If y = (x - 4)2, find the value of y when x = 5.​
vovangra [49]

Answer:

y = 2

Step-by-step explanation:

<u>Step 1:  Plug in 5 for x</u>

y = ((5) - 4) * 2

y = (1) * 2

<em>y = 2</em>

<em />

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7 0
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Ainat [17]

Answer:

f(-5) = -43

Step-by-step explanation:

Step 1: Define

f(x) = -2x² + 7

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Step 2: Substitute and Evaluate

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