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2 answers:
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Answer:
19.5°
Explanation:
The energy of the mass must be conserved. The energy is given by:
1)
where m is the mass, v is the velocity and h is the hight of the mass.
Let the height at the lowest point of the be h=0, the energy of the mass will be:
2)
The energy when the mass comes to a stop will be:
3)
Setting equations 2 and 3 equal and solving for height h will give:
4)
The angle ∅ of the string with the vertical with the mass at the highest point will be given by:
5)
where l is the lenght of the string.
Combining equations 4 and 5 and solving for ∅:
6)
Answer:
The value of impulse of the net force on the ball during its collision with wall is
The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N
Explanation:
Mass of the ball = 0.5 kg
Horizontal velocity = 20
Velocity after collision = - 10
(A). Impulse of the net force on the ball during its collision with wall is
I = 0.5 × (20 + 10)
This is the value of impulse of the net force on the ball during its collision with wall.
(B). The magnitude of average horizontal force
Where F = Force
I = impulse & t = time interval = 0.001 sec
F = 15000 N
This is the value of average horizontal force that the wall exerts on the ball during the impact.