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3 years ago

A sound is recorded at 19 decibels. What is the intensity of the sound?

Physics

1 answer:

aalyn [17]3 years ago

4 0

Answer:

79·433 × $10^{-12}$ W/m²

Explanation:

Given intensity of sound in decibels is 19

Formula for intensity of sound in decibels is

where

$I_{1}$ is the intensity of sound measured in decibels

I is the intensity of sound measured in W/m²

$I_{0}$ is the intensity of the sound that is taken as standard and it's value is equal to $10^{-12}$ W/m²

By applying the formula

19 = 10 × ㏒(I ÷ $I_{0}$ )

⇒ 1·9 = ㏒(I ÷ $I_{0}$ )

⇒ antilog(1·9) = I ÷ $I_{0}$

⇒ 79·433 = I ÷ $10^{-12}$

⇒ I = 79·433 × $10^{-12}$ W/m²

∴ Intensity of sound = 79·433 × $10^{-12}$ W/m²

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Answer:

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Explanation:

As we know that base of the slab is given as

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3 years ago

PLEASE HELP!

WINSTONCH [101]

So you would first multiply 400 by 2 which equals 800, then add 30 which is 830.
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3 years ago

(b) A cylinder of cross-sectional area 0.65m2 and

VLD [36.1K]

Answer:

The volume of the cavity is 0.013m^3

Explanation:

To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:

Step one:

Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.

Volume of the cylinder = 2.1 / 11.053 =0.19 $m^{3}$

Step two:

From the volume of the cylinder, we can get the radius of the cylinder.

$radius = \sqrt{\frac{V}{\pi \times h}} = \sqrt{\frac{0.19}{\pi \times 0.32}} =0.44m$

Step three:

From the cross-sectional area, we can obtain the radius of the cavity.

Let the radius of the cavity be = r, while the radius of the cylinder be = R

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$\pi({R^2}-r^2) = CSA\\0.65 = \pi (0.32^2-r^2)\\r= 0.115m$

Step Four:

calculate the volume of the cavity using volume = $\pi r^2 \times h$

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3 years ago

Which of the following types of waves carries the most energy?

Umnica [9.8K]

C.) ultraviolet
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3 years ago

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Three pairs of wooden dowel rods are mounted on a wooden platform. Small plastic cylinders are attached to their ends; the cylin

katovenus [111]

The natural frequency of this dowel rod is determined as 0.5 Hz.

<h3>What is frequency?</h3>

The frequency of an object is the number of complete revolutions per second.

F = n/t

where;

n is number of compete revolution
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F = 1/2

F = 0.5 Hz

Thus, the natural frequency of this dowel rod is determined as 0.5 Hz.

Learn more about frequency here: brainly.com/question/301048
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2 years ago