Question

A sound is recorded at 19 decibels. What is the intensity of the sound?

Answer 1

Answer:

79·433 × $10^{-12}$ W/m²

Explanation:

Given intensity of sound in decibels is 19

Formula for intensity of sound in decibels is

$I_{1}$ = 10 × ㏒(I ÷ $I_{0}$)

where

$I_{1}$ is the intensity of sound measured in decibels

I is the intensity of sound measured in W/m²

$I_{0}$ is the intensity of the sound that is taken as standard and it's value is equal to $10^{-12}$ W/m²

By applying the formula

19 = 10 × ㏒(I ÷ $I_{0}$)

⇒ 1·9 = ㏒(I ÷ $I_{0}$)

⇒ antilog(1·9) = I ÷ $I_{0}$

⇒ 79·433 = I ÷ $10^{-12}$

⇒ I = 79·433 × $10^{-12}$ W/m²

∴ Intensity of sound = 79·433 × $10^{-12}$ W/m²