The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is
seconds
So, the time required for 200 wing beat
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...

So, the time required for one wing beat is 5 milliseconds.
Answer:
C) Ken added 19 to both sides of the equation rather than subtracting 19.
Step-by-step explanation:
I Just Took The Test On Edge
The prime factors are: 2 x 2 x 3 x 3
Answer:
(-4,-1) --------> (-4,1)
Step-by-step explanation:
P(x,y) -----------> P' (x, -y)
y-axis