Answer:
A and B are both 3.
Step-by-step explanation:
The given polynomial is
.
We factor the GCF to obtain:

We factor further by grouping to get:
![3x[x^2(x-6)+3(x-6)]](https://tex.z-dn.net/?f=3x%5Bx%5E2%28x-6%29%2B3%28x-6%29%5D)

We compare this to the given factored expression:

We must have A=3,B=3, C=-6
Answer:
13,784
Step-by-step explanation:
no because you are not distributing numbers that multiply with each other and form new expressions