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3 years ago

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Given the functions, f(x) = 5x2 - 3x + 1 and g(x) = 2x2 + x - 2, perform the indicated operation. When applicable, state the dom

ain restriction.

1 answer:

RUDIKE [14]3 years ago

3 0

You plug in 1,2,3 and so on in the X and you graph , i think

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6x44<br> hbgvtfwtydtwftdftwyfdywdwd

Ipatiy [6.2K]

Answer:

264

Step-by-step explanation:

well you could have just used a calculator!

3 0

3 years ago

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HELP PLZZZ WHATS 2+2+5+9+100-76=?

Novosadov [1.4K]

Answer:

42

Step-by-step explanation:

"alexa what's 2+2+5+9+100-76" Imao

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3 years ago

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A man standing on a lighthouse at a height of 124 feet sights two boats directly in front of him. One is at an angle of depressi

Ksivusya [100]

Answer:

$125\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ABC find the length side BC

we know that

$tan(62\°)=\frac{124}{BC}$

$BC=\frac{124}{tan(62\°)}$

step 2

In the right triangle ABD find the length side BD

we know that

$tan(33\°)=\frac{124}{BD}$

$BD=\frac{124}{tan(33\°)}$

step 3

we know that

The distance between the two boats is the length side CD

$CD=BD-BC$

substitute the values

$CD=\frac{124}{tan(33\°)}-\frac{124}{tan(62\°)}=125\ ft$

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3 years ago

Paula had 1/3 of a yard of material. She needed to make 4 gifts using the material. What fraction of the material will be used f

dlinn [17]

1/12 yards taken for each gifts

Explanation:

$\ \sf total \ material \rightarrow \dfrac{1}{3}$

$\ \sf each \ gift \ material \rightarrow \dfrac{1}{3} \div 4$

$\ \sf each \ gift \ material \rightarrow \dfrac{1}{3} \ * \ \dfrac{1}{4}$

$\ \sf each \ gift \ material \rightarrow \dfrac{1}{12}$

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2 years ago

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Zeke deposited $300 into a savings account. The interest rate on the account is 3%, compounded continuously. To determine how lo

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$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array} ~\hspace{4em} \begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array}$

$\bf \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\textit{let's use this one}}{log_a a^x = x}\qquad \quad a^{log_a x}=x \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 900=300e^{0.03t}\implies \log_e(900)=\log_e(300e^{0.03t})$

$\bf \log_e(900)=\log_e(300)+\log_e(e^{0.03t})\implies \ln(900)=\ln(300)+0.03t\cdot \ln(e) \\\\\\ \ln(900)-\ln(300)=0.03t\implies \ln\left( \cfrac{900}{300} \right)=0.03t\implies \ln(3)=0.03t$

3 0

3 years ago