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kodGreya [7K]
2 years ago
8

How do you subtract fractions? I keep forgetting.

Mathematics
2 answers:
Vsevolod [243]2 years ago
6 0

so if its like 1/2 - 3/8 you first make 1/2 to 4/8 then subtract

juin [17]2 years ago
4 0

keep your denominator the samem...ithink

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7. Which statement is true about rationals?
scZoUnD [109]

Answer:

answer is A

Step-by-step explanation:

5 0
2 years ago
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Y = 2x - 8 3x - 2y = 13​
SSSSS [86.1K]

Answer:

{x,y} = {3,-2}

Step-by-step explanation:

// Solve equation [1] for the variable  y

 [1]    y = 2x - 8

// Plug this in for variable  y  in equation [2]

  [2]    3x - 2•(2x-8) = 13

  [2]    -x = -3

// Solve equation [2] for the variable  x

  [2]    x = 3

// By now we know this much :

   x = 3

   y = 2x-8

// Use the  x  value to solve for  y

   y = 2(3)-8 = -2

Solution :

{x,y} = {3,-2}

8 0
3 years ago
Match each value with its formula for ABC.
Ivahew [28]

For the triangle ABC use the sine theorem:

\dfrac{a}{\sin A}= \dfrac{b}{\sin B}= \dfrac{c}{\sin C}.

1. From \dfrac{a}{\sin A}= \dfrac{b}{\sin B} you have \dfrac{a}{b} \cdot \sin B=\sin A.

2. From \dfrac{b}{\sin B}= \dfrac{c}{\sin C} you have \dfrac{b}{c} \cdot \sin C=\sin B.

3. From \dfrac{a}{\sin A}= \dfrac{c}{\sin C} you have \dfrac{c}{a} \cdot \sin A=\sin C.

4. From \dfrac{a}{\sin A}= \dfrac{c}{\sin C} you have \dfrac{\sin A}{\sin C} \cdot c=a.

5. From \dfrac{a}{\sin A}= \dfrac{b}{\sin B} you have \dfrac{\sin B}{\sin A} \cdot a=b.

6. From \dfrac{b}{\sin B}= \dfrac{c}{\sin C} you have \dfrac{\sin C}{\sin B} \cdot b=c.

5 0
3 years ago
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Write an equation for a circle with center at (6, –2) and diameter = 12.
SVEN [57.7K]
(x+6)2+(y-10)2=36 , would be your equation.
4 0
3 years ago
What is the area of the figure
Semenov [28]

Answer:

Area of the figure = 36 in²

Step-by-step explanation:

Area of the given composite figure = Area of the rectangle ABCE - Area of triangle CDE

Area of rectangle ABCE = Length × Width

                                        = AB × AC

                                        = 6 × 8

                                        = 48 in²

Area of triangle CDE = \frac{1}{2}(\text{Base})\times (\text{Height})

                                   = \frac{1}{2}(6)(4)

                                   = 12 in²

Now area of the composite figure = 48 - 12

                                                         = 36 square inch

4 0
2 years ago
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