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kakasveta [241]
2 years ago
13

Graph the point (-1, 3) on the coordinate plane.

Mathematics
1 answer:
Tatiana [17]2 years ago
6 0

Answer:

go back one and up three

Step-by-step explanation:

Like and give 5 star rating

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Given that (2,8) is on the graph of f(x),find the corresponding point for the function -3/4 f(x)
yuradex [85]

Answer:

Corresponding point to (2,8) along -3/4 f(x) = ( -1.5 , -6 )

Explanation:

 When a graph f(x) is multiplied by a factor k, the points on the graph also changes by (kx, ky).

Here it is given that (2,8) is on the graph of f(x)

Now we need to find corresponding point to (2,8) along -3/4 f(x)

x - coordinate = \frac{-3*2}{4} =-1.5

y - coordinate = \frac{-3*8}{4} =-6

So corresponding point to (2,8) along -3/4 f(x) = ( -1.5 , -6 )

8 0
3 years ago
One hundred coins weigh 346 grams. How many grams does 1 coin weigh?
Pani-rosa [81]

Answer:

3.46 grams

Step-by-step explanation:

346/100 - 3.46

3 0
3 years ago
18 (- x - 2) - 4 (- 9 + 3x) = -14<br><br> Find the value of X
igomit [66]

Answer:

x = 7/15

Step-by-step explanation:

you can check by replacing the x with the number I gave you

5 0
2 years ago
Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

d = \sqrt{89

d = 9.4

Solving (b): The radius;

In (a), we have:

r = 3 --- circle P

r = 2 --- circle Q

By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

4 0
3 years ago
PLEASE HELP!!!
kvasek [131]

Answer:

D

Step-by-step explanation:

Then you find the intersection and get the bisector without a protractor :)

7 0
3 years ago
Read 2 more answers
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