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3 years ago

How do you divide fractions?

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

Answer:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction. The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

Step-by-step explanation:

Greeley [361]3 years ago

6 0

Answer:

hey mate !

let me do a example sum for u ,

$\frac{11}{5} \: \div \: \frac{17}{5} \\ \\ = > \: so \: first \: write \: the \: reciprocal \: of \: the \: second \: fraction \: \\ ( \: reciprocal \: of \: \frac{17}{5} = \frac{5}{17} ) \\ = > \: now \: multiply \: them \: \\ - > \: \frac{11}{5} \times \frac{5}{17} = \frac{11}{17} \: \\ when \: u \: simplify \: u \: get \: the \: ans \: as \: \frac{11}{17}$
hope it helps mate !!

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How many solutions does this system have? y=3/4x-5 -3x+4y=-20?

Komok [63]

4y=-20+3x and 4y=13.6x-20
so
-20+3x=13.6x-20
3x=13.6x
3=13.6 so it is wrong and system doesn’t have solution

4 0

4 years ago

Need steps on how to factor 3x^4 + x^3 + 6x^2 + 2x

ella [17]

Answer:

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

x^3 + 2x^3 + 3x^6

Step-by-step explanation:

3x^4 + x^3 + 6x^2 + 2x

3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

x^3 + 2x^3 + 3x^6

5 0

3 years ago

PLZ HELP ASAP WILL MARK BRAINLIEST

RSB [31]

Answer:

72 $\sqrt{3}$

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = $\frac{1}{2}$ × d₁ × d₂ (d₁ and d₂ are the diagonals )

The diagonals bisect each other at right angles

d₁ = 2 × 6 = 12

Use the tangent ration in the upper left right triangle and the exact value

tan60° = $\sqrt{3}$

tan60° = $\frac{opposite}{adjacent}$ = $\frac{opp}{6}$ = $\sqrt{3}$ ( multiply both sides by 6 )

opp = 6 $\sqrt{3}$ , then

d₂ = 2 × 6 $\sqrt{3}$ = 12 $\sqrt{3}$

Thus

A = $\frac{1}{2}$ × 12 × 12 $\sqrt{3}$ = 6 × 12 $\sqrt{3}$ = 72 $\sqrt{3}$

3 0

3 years ago

Please anyone help me answer this question am giving the brainliest

DochEvi [55]

Answer:

(-3/2x+1) + (3/x-1)

Step-by-step explanation:

Dont put the answer in parenthesis, I just did that to seprate it so it was easier to read. If you need it to be put in word form for it to be easier for you to understand, its "negative three divided by two x plus one, plus 3 divided by x minus 1"

First, rewrite the expression as 3x+6/2x^2+x-2x-1

Then, factor the expression, 3x+6/x*(2x+1)-(2x+1) (*=multiply)

Then, write a new fraction for each factor in the denominator, then write a new fraction, 3x+6/(2x+1)*(x-1) to (A)/2x+1 + B/x-1)

Then write terms in the numerators, for now we will use A and B.

Now we set the sum of the fractions equal to the original fraction.

3x+6/(2x+1)*(x-1) = A)/2x+1 + B/x-1).

Then reorder and group the terms, giving you 3x+6=(A+2B)x+(-A+B).

Now equate the coefficiants, {6= -A+B, 3= A+2B

Then substitute back, (A, B)=(-3, 3)

Now finally, just rewrite the fraction. (-3/2x+1) + (3/x-1)

Hope this helps! Sorry its kind of long.

6 0

3 years ago

PLEASE HELP URGENT MY MOM WILL GROUND ME IF I DONT FINISH THIS LOL

exis [7]

Step-by-step explanation:

Hope it helps you in your learning process.

8 0

3 years ago