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notka56 [123]
4 years ago
7

Community Service You are making a bulletin board to

Mathematics
1 answer:
liubo4ka [24]4 years ago
3 0

Answer:

72 ads

Step-by-step explanation:

Let

x -----> the number of ads

we know that

5 sheets of construction paper for a title banner plus the number of ads multiplied by one quarter of sheet must be equal to 23 sheets of construction paper

so

The linear equation that represent this problem is

\frac{1}{4}x+5=23

Solve for x

Multiply by 4 both sides to remove the fraction

x+20=92

Subtract 20 both sides

x=92-20

x=72\ ads

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The value of 3^3 + 4^2 = ___.
miss Akunina [59]
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷  3^{3}  = 27

4^{2} = 16

16 + 27 = 43

The answer is 43.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Read 2 more answers
Hello HELP THIS IS DUE VERY SOON
shepuryov [24]

Answer: D) 92.4 m

Step-by-step explanation: Use the right angle perimeter formula

4 0
3 years ago
Write the equation of a line with a slope of -7/2 passing through the point 2,-4
fiasKO [112]

Answer:

y = -7/2x+3

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = -7/2 x+b

Substitute the point into the equation

-4 = -7/2(2) +b

-4 = -7+b

Solving for b

-4+7 = -7+b+7

3 = b

The equation is y = -7/2x+3

5 0
3 years ago
If the equation y=-5x+12 is translated up five units, what would the new equation be?
Maurinko [17]

Answer:

y=-5x+17

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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