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3 years ago

6

I needed to write something long enough to post this

2 answers:

Dmitry [639]3 years ago

8 0

Answer: It should be the first one again.

jenyasd209 [6]3 years ago

7 0

The first graph is the correct answer!

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What is the solution set of these system5x-2y=17 and 4x-7=13?

MatroZZZ [7]

Answer:

x=5

y=4

Step-by-step explanation:

Step 1:

Let us solve for <em>x</em> using the $4x-7=13$ equation by <u>isolating terms containing the variable</u>:

$4x-7=13\\4x=20\\\fbox{x=5}$

Great! <em>x</em> is 5... let's find <em>y</em>.

Step 2:

Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:

$5x-2y=17\\$

<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.

$5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}$

<em>I hope this helps! Let me know if you have any questions :)</em>

3 0

3 years ago

In the number 340.79 , the 0 is in what place

kirill115 [55]

Answer:

units

Step-by-step explanation:

The zero (0) is in the units place. unit = 1

4 0

4 years ago

Read 2 more answers

Plot the point first and then use the slope from that point<br> (-4,3) M=-1/2

Goshia [24]

Plot the point first and then use the slope from that point<span> - 3270801. ... </span>Plot the point first and then use the slope from that point (-4,3<span>) </span>M=-1/2<span>. 0</span>

7 0

3 years ago

Solve for x, y, and all of the missing angles. d = (2y+2) c = (3y + 18) a 50° b = (2x + 4) b degrees b degrees . degrees d = deg

CaHeK987 [17]

Answer:

that answer was wrong your dum

Step-by-step explanation:

4 0

3 years ago

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

3 years ago