(4y + 1)(2y + 1) -- Unfortunately I can't help with the grid part
Step-by-step explanation:
Multiply the a and c term (8 * 1) to get 8. Think of what factors of 8 would add up to your b term (6), which would be 4 and 2. Rewrite your equation as 8y^2 + 4y + 2y + 1 and consider one half at a time and factor them individually. For the left, that'd be 4y(2y + 1), and for the right, you can't factor anything so it's just 1(2y + 1). Check that the things inside the parentheses are the same, which they are, and add the things you factored out and multiply that by the part in the parentheses for (4y + 1)(2y + 1).
