Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be

P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be

p(B) = 1/2
Answer
There a 9 fries for every 14 orders of watermelon.
Step-by-step explanation:
Percent of requests for Joseph were:

Total number of requests:
320+750+620+930+800+180=
1070+1550+980=
2620+980=3600.
Which means the percentage is:

Answer:
- For the data distribution question I think it's the middle two (with the 3 as the center)
- For the histogram (lol I say bar chart or bar graph) I'd say it's 24.
Step-by-step explanation:
- For number 1, since both of them have 3 as the most occurring and the middle number, I think it's those two.
- For number 2, I added the frequencies for each bar together to equal 24.
I'm not quite sure about my answers though, sorry :(
Hope I helped :)