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Citrus2011 [14]
3 years ago
11

ik how to do the calculation but 36 doesn't come in 5's table (the table I'm using to cancel) so i don't know how to cancel 150

by 360 thus i can't find the angles for it​

Mathematics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:Take as an example

Step-by-step explanation:

7,203 x 6,892. If I want to know that exactly, then I reach for Mathematica (or if I absolutely have to, I reach for pencil and paper to apply multiplication in columns). But often I just need a rough answer, so I mentally convert this to 7,000 x 7,000 = 7 x 7 x 1,000 x 1,000 = 49,000,000. More formally I am converting the numbers the nearest approximation of the form k x 10n where k ∈ {the set of numbers for which I know times tables}. Then I use the times tables on the remaining significant digits and implicitly use the 10 times table to get the magnitude right. In this case the real answer is:

You might be interested in
D=(107-115)^2+(-49+-69)^2​
ladessa [460]

Answer:

d=13988 or d=1.3988 x 10^4

Step-by-step explanation:

d=(-8)^2+(-118)^2

d=64+13924

d=13988

6 0
3 years ago
Select the appropriate technique with the problem you are looking for.
Alenkinab [10]

Answer:

A, B, C, D

Step-by-step explanation:

(A) Checking the Equal Variance Assumption, the appropriate technique to use is:

- The ANOVA (Analysis of Variance) F test

- Plot residuals against fitted values

(B) Checking the Normal Assumption, the appropriate techniques to use are:

- Test for Kurtosis & Skewness

- Kolmogorov-Smirnov Test

- Q-Q Plots (the graphical method) also known as Quantile Plot

- Do not use a histogram; it is not advisable

(C) Checking for Model Misspecification, the appropriate techniques to use are:

- The Ramsey Regression Specification Error Test; also called RESET

- The Davidson & MacKinnon J. Test

(D) Checking for dependent errors, the appropriate technique to use is:

- Plot residuals against time variables

6 0
3 years ago
. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu
jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0
2 years ago
Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr
Jobisdone [24]

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let M(a) = 40.8-1.1\cdot a, where a is the age of the dairy cow, measured in years, and M(a) is the predicted milk production, measured in gallons per week.

Besides, we consider a_{1} and a_{2}, such that a_{1}\ne a_{2}, we define the difference between predicted milk productions (\Delta M) below:

\Delta M = -1.1\cdot (a_{2}-a_{1}) (1)

If we know that a_{1} = 5\,yr and a_{2} = 10\,yr, then the difference between predicted milk productions is:

\Delta M = -1.1\cdot (10-5)

\Delta M = -5.5\,\frac{gal}{week}

That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.

6 0
2 years ago
A certain forest covers an area of 4800 km^2 . Suppose that each year this area decreases by 5.25% . What will the area be after
9966 [12]

Answer:

the area after 6 years is  3,473 km^2

Step-by-step explanation:

The computation of the area after 6 years is as follows:

= Area × (1 - decreased percentage)^number of years

= 4,800 km^2 × (1 - 5.25%)^6

= 4,800 km^2 × 0.9475^6

= 3,473 km^2

Hence, the area after 6 years is  3,473 km^2

5 0
3 years ago
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