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GaryK [48]
3 years ago
14

A game you wanted was discounted 45% and now costs $26.29 what did the game cost before the discount

Mathematics
1 answer:
meriva3 years ago
3 0

Answer: I think its $58.4

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The graph above is the graph of: y = | x + 4 | − 2 y = | x − 4 | − 2 y = | x − 2 | − 4
Liono4ka [1.6K]

We need to identify the equation of the graph given.

This graph corresponds to a translation of the graph described as:

y=|x|

Comparing the graph given with the one above, we can see it was shifted 4 units to the left.

When we translate the graph of a function f(x) d units to the left, it is transformed as:

f(x)\rightarrow f(x+d)

4 0
1 year ago
Evaluate the expression when m= -2.8 and n=-6.3.<br> 4n - 6m
Alex73 [517]
Answer is 42, hope this helps
5 0
3 years ago
1. Gina saved 3,000 in an account that offered 3.8% simple interest for 240 days. Find the accumulated amount using ordinary sim
mash [69]

Answer:

3,114 in 240 days

Step-by-step explanation:

3000 x 0.038=114

114+3000=3114

6 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
How do you solve the equation 5x= 1 2/3
disa [49]
I hope it helps you get it right

3 0
3 years ago
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