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andrew-mc [135]
3 years ago
14

Plz help

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Solution: x = 2, y = -1 or (2, -1)

Step-by-step explanation:

Equation 1:  2x + y = 3

Equation 2: 5x - 2y = 12

Using the substitution method:

Transform the Equation 1 into its slope-intercept form:

2x + y = 3

2x - 2x + y = -2x + 3

y = 2x + 3

Substitute the value of y = -2x + 3 into Equation 2:

5x - 2y = 12

5x - 2(-2x + 3) = 12

5x + 4x - 6 = 12

9x - 6 = 12

9x - 6 + 6 = 12 + 6

9x = 18

9x/9 = 18/9

x = 2

Substitute the value of x = 2 into Equation 2 to solve for y:

5x - 2y = 12

5(2) - 2y = 12

10 - 2y = 12

10 - 10 - 2y = 12 - 10

-2y = 2

-2y/-2 = 2/-2

y = -1

Double-check whether the values for x and y will provide a true statement for both equations:

Equation 1:  2x + y = 3

2(2) + (-1) = 3

4 - 1 = 3

3 = 3 (True statement)

Equation 2: 5x - 2y = 12

5(2) - 2(-1) = 12

10 + 2 = 12

12 = 12 (True statement)

Therefore, the correct answers are: x = 2; y = -1 or (2, -1).

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Answer:

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Step-by-step explanation:

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1) You're looking for factors of -24 that have a sum of -5. It can be useful to simply list the factor pairs. Since you want a negative sum, you may want to start with the most negative factors and work up from there.

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So, the left- and right-quadrants are filled with -8 and 3.

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2) You are given the factors, so all you need to do is form the product and sum.

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<em>Additional comment</em>

Any sort of factoring is much easier to do if you have memorized your multiplication tables, preferably through 12×12. It is also helpful if you're familiar with divisibility rules—at least for single-digit numbers. I've seen college students struggle trying to do factoring using a calculator. It's not pretty. Many folks learn their times tables up to 10×10 by the end of 3rd grade.

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