Answer:
0.625
Step-by-step explanation:
Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.
Since A1 and A2 are mutually exclusive and exhaustive, we can say
b) P(B) = P(A1B)+P(A2B)
Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads.
c) Using Bayes theorem
conditional probability that it wasthe biased coin
=
d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin=
Answer:
5 months
Step-by-step explanation:
Equate the formulas for the weights of the two boys:
J's weight = 120 lb + (10 lb/mo)m = D's weight = 150 lb + (4 lb/mo)m
Solve as follows: Subtract 120 lb from both sides:
(10 lb/mo)m = 30 lb + (4 lb/mo)m.
Then: (6 lb/mo)m = 30 lb, and m = (30 lb) / (6 lb/mo) = 5 months
3,7,11,15,19,23,27,31
32 = 8th term.
The common difference is +4
you have 10 fish and 3 died (must not have been taking very good care of them ?), but it didnt say that you cleaned them out ...
so you still have 10 fish in the tank
8 more got put in, so 10 + 8 = 18 fish
2 died but you STILL didnt take them out, so you have 18 fish in the tank now.