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LiRa [457]
3 years ago
12

The function f(x) has an average rate of change on the interval -2≤x≤3 of 17/5. If f(-2)=9 then which of the following is the va

lue of f(3)?
(1)12.4
(2)17
(3)21.8
(4)26

Mathematics
1 answer:
anastassius [24]3 years ago
5 0

Answer:

f(3) = 26

Step-by-step explanation:

Average rate of change of a function on an interval is;

f(a) - f(b)/(a-b)

Here, we want to find the value of f(-3)

To find the average rate of change on the given interval;

we have;

f(3) - f(-2)/3-(-2) = 17/5

f(3)-9/5 = 17/5

Since denominator is same, we equate numerator;

f(3)-9 = 17

f(3) = 17 + 9

f(3) = 26

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When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

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The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

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A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

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Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

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We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

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