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kodGreya [7K]
3 years ago
9

If: A + B = 8 [] C - A = 6 [] A + C = 13 [] then A=______ B=_______C=_______ (Hint:A,B, and C are not whole numbers!)

Mathematics
1 answer:
Komok [63]3 years ago
7 0

Answer:

A=3.5

B=4.5

C=9.5

Step-by-step explanation:

You can solve A and C with the last two equations through trial and error

then you plug in the solved A into the first equation to solve for B

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Y = 3x - 4<br> y = 4 + x
Andrei [34K]
Is This Substitution?

Cause if it is, then Y = 3x - 4
                              Y = 4 + x
= (4, 8)
7 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Calculate the capacity in liters of a tin 20m by 15m by 10m.​
rusak2 [61]
20 * 15 * 10 *10^-6
= 0.003
5 0
4 years ago
Attached please find my maths problem to be solved and graphed
ki77a [65]

Answer:

Attached is the sketch

X-axis intersections:

(-3,0)

(0,0)

(1,0)

Points of inflection:

(-1,319,-2.881) Concave upward

(0.569,1.041) Concave downward

Step-by-step explanation:

Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!

8 0
3 years ago
If a triangle has a 30° angle and a 60° angle, then the hypotenuse of the triangle is twice the
Dimas [21]
I believe it’s false, sorry if I’m wrong
5 0
3 years ago
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