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3 years ago

If: A + B = 8 [] C - A = 6 [] A + C = 13 [] then A=__ B=_C=_____ (Hint:A,B, and C are not whole numbers!)

Mathematics

1 answer:

Komok [63]3 years ago

7 0

Answer:

A=3.5

B=4.5

C=9.5

Step-by-step explanation:

You can solve A and C with the last two equations through trial and error

then you plug in the solved A into the first equation to solve for B

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The pairs that equal to 4x-y=10

Tcecarenko [31]

You can work it out by using trial and error

so you get

x=3 , y=2

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3 years ago

Draw a pair of adjacent supplementary angles so that one has a measure of 15 degrees

Nat2105 [25]

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2 years ago

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3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

3 years ago

Read 2 more answers

What is the slope of the line?

sineoko [7]

Answer:

3/4

Step-by-step explanation:

You can do this two different ways. Both include picking two points where the line crosses a corner. I'm using (0,-1) and (4,2). Now here you can either use

Slope= $\frac{Rise}{Run}$

or $\frac{y2-y1}{x2-x1}$

If you use the first one start at point (0,-1) and go to point (4,2) and count how many it goes up (rise) and then put that over how many it goes to the right (run).

If you use the second one then plug in the numbers.

y2=second y point

y1=first y point

x2=second x point

x1=first x point

$\frac{2-(-1)}{4-0}$ Now just solve.

$\frac{3}{4}$

4 0

3 years ago

If: A + B = 8 [] C - A = 6 [] A + C = 13 [] then A=______ B=_______C=_______ (Hint:A,B, and C are not whole numbers!)

If: A + B = 8 [] C - A = 6 [] A + C = 13 [] then A=__ B=_C=_____ (Hint:A,B, and C are not whole numbers!)