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Anestetic [448]
3 years ago
15

Hi all, please help me with this problem(It's Algebraic Expression's!)I suck in maths :/​

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

3rd side = 2x + 6y

Step-by-step explanation:

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See The Attachment My Friend.....

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Jacket is 125.000 tax is 5.5%
kykrilka [37]

Answer:

$131.88

hope this helps

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please Help!! I always get stuck on these and I am super confused.
kifflom [539]
I believe it would C.
7 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7Bx%20%2B%202%7D%20%20-%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%5Cfrac%7B8%7D%7B9%
ser-zykov [4K]

3^{x + 2} - 3^{x} = 3^{x}* 3^{2} - 3^{x} = 9(3^{x}) - 1(3^{x}) = 8(3^{x})

3^{x + 2} - 3^{x} = \frac{8}{9}

⇒ 8(3^{x}) = \frac{8}{9}

⇒ 3^{x} = \frac{1}{9}   <em>multiplied both sides by 8</em>

⇒3^{x} = \frac{1}{3^{2} }

⇒ 3^{x} = 3⁻²

⇒ x = -2

Answer: x = -2

6 0
3 years ago
Charlie bought 40 oz of flour for his bakery. He used 18.3 oz to make a loaf of bread, and 0.95 oz for each muffin. How many muf
Furkat [3]

Division is one of the four fundamental arithmetic operations. With the leftover flour of 7.45oz, charlie can make approximately 8 muffins.

<h3>What is Division?</h3>

The division is one of the four fundamental arithmetic operations, which tells us how the numbers are combined to form a new one.

A.) The total flour Charlie has was 40 oz, out of this he used 18.3 oz of flour. The amount of flour left now would be 21.7 (40-18.3).

Since a single muffin uses 0.95 oz of flour, therefore, the number of muffins Charlie made will be,

Number of muffins = 21.7/0.95 = 22.84 ≈ 23 muffins

B.) When Charlie had 7.45 oz of flour leftover, then the number of muffins would be,

Number of muffins = 7.45/0.95 = 7.84 ≈ 8 muffins

Hence, with the leftover flour of 7.45oz charlie can make approximately 8 muffins.

Learn more about Division:

brainly.com/question/369266

#SPJ1

8 0
2 years ago
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