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OlgaM077 [116]
3 years ago
13

A delivery truck drove 203 mi in 3.5 h. After unloading and loading new cargo, it traveled on another 243 mi for 4.5 h.

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0
The answer is 55.75! Trust me I took a test on this and its the right one.
Tatiana [17]3 years ago
3 0
The answer is 55.75. Hope this helps out =3
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The absolute value of a negative integer
mezya [45]
The absolute value of a negative integer is the positive number of the same integer. I hope that made sense.
5 0
3 years ago
3. Find the volume of the pyramid.
Gnoma [55]

Answer:

916.11\:ft^{3}

Step-by-step explanation:

Volume of the hexagonal pyramid =  1/3\times (area\: of \: hexagonal\:base)\times height

Here sides of hexagonal base = 9 ft

So, Area of hexagon = 6\times \frac{\sqrt{3} }{4} a^{2}

6\times \frac{\sqrt{3} }{4} \times 9 \times 9

= 210.5

Height is given, 13 ft

So, volume = 1/3\times 210.5\times 13

= 916.11\: ft^{3}

<u>OAmalOHopeO</u>

5 0
3 years ago
Kadeem rode his bike at a constant speed. He rode 1 mile in 5 minutes. Which equation represents the amount of time in minutes,
sashaice [31]

Answer:

A

Step-by-step explanation:

Speed is the rate of change of distance over time.

The equation represents the amount of time t is \mathbf{t = 5 d}t=5d

Speed is calculated using:

\mathbf{Speed = \frac{distance}{time}}Speed=timedistance

When distance = 1 mile, and time = 5 minutes.

We have:

\mathbf{Speed = \frac{1}{5}}Speed=51

When distance = d, and time = t

We have:

\mathbf{Speed = \frac{d}{t}}Speed=td

Substitute \mathbf{Speed = \frac{1}{5}}Speed=51

\mathbf{\frac{d}{t} = \frac 15}td=51

Cross multiply

\mathbf{t = 5 \times d}t=5×d

\mathbf{t = 5 d}t=5d

Hence, the equation represents the amount of time t is \mathbf{t = 5 d}t=5d

5 0
3 years ago
Read 2 more answers
1000p for an answer pleaseeeeee
zepelin [54]
X=17.3
but the 3 has a line above. which means repeated 
4 0
3 years ago
Read 2 more answers
How do I solve this part a,b
Svetach [21]

Answer:

the anwser you put is correct

Step-by-step explanation:

congragulations! glad i could help :)

4 0
3 years ago
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